Let x = speed of plane in still air
y = speed of wind
Distance = (speed)(time)
speed with a head wind = x - y, so 1000 = (x - y)(4)
Therefore, 4x - 4y = 1000
{3 hr 20 min = 3 hr + 1/3 hr = 10/3 hr}
speed with a tail wind = x + y, so 1000 = (x + y)(10/3)
Therefore, 10x + 10y = 3000
We have 4x - 4y = 1000
10x + 10y = 3000
divide 4x - 4y = 1000 by 4 to get x - y = 250
divide 10x + 10y = 3000 by 10 to get x + y = 300
We have: x - y = 250
x + y = 300
Adding the equations, we obtain 2x = 550
x = 275 and 275 + y = 300
y = 25
The speed of the plane in still air is 275 mph and the speed of the wind is 25 mph.