If 740 J of heat is added to 39 mL of Carbon tetrachloride initially at 80.0 C, what is its final temperature, in celsius?

Question

H_fus=2.52 kJ/mol H_vap=32.54 kJ/mol m.p.=-22.29C b.p.=76.72C c_solid=44.22 J/molC c_liquid=131.3 J/molC c_gas=82.65 J/molC d_solid=1.81 g/mL d_liquid=1.59 g/mL

Answer 1

Initially, it's at 80 C. The boiling point is 76.72 C, so it is a gas.

Use the volume of the sample and the density of the gas to determine the mass.

This problem does not give the density of the gas, so the mass of the gas cannot be determined from the mL given, so the problem has not given enough information to provide the answer.