Drew M.

asked • 12/06/19

Find the volume of the solid generated by revolving the region bounded by y=x and y=x^2 about the line x= -1

I have y=x as a upward diagonal line, y=x^2 as the upward facing parabola. and -1 down the inner left side of the graph. How am I suppose to put this into an equation? I'm having trouble understanding what this question is asking me to do honestly. Thanks in advance!

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Doug C. answered • 12/07/19

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Drew M.

Thank you for help setting up this equation doug. I was confused because I'm used to problems stating "about the 'blank' axis" so I wanted to know if x=-1 is suppose to lead me to believe its about the y-axis in this case? I got my answer pi/2 but i just wanted to know why it didn't say about any axis. Sorry I'm still new to these concepts!
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12/07/19

Drew M.

*Doug
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12/07/19

Doug C.

So the axis of revolution does not have to be the x-axis or y -axis, it can be any horizontal or vertical line. So let's say the axis of revolution is the line x = -3 and you are using the shell method and integrating along the x-axis from 1 to 4 (for example). The shell method requires you to come up with an expression for the "average radius". The right-hand end point of a typical radius will be represented by "x". The distance from the axis or revolution to that x-value you can think of as right-hand endpoint minus left-hand endpoint, in this example that would be x - (-3) or x + 3.
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12/08/19

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