For the following spinner B, R, J, S find the Probability (1st spin is B and 2nd spin is S)?

Question

For the following spinner: B, R, J, S find the Probability (1st spin is B and 2nd spin is S)?

Please, help. I have no idea how to figure this out, and my professor is not good. He just doesn't explain almost anything, and uses different exercises to the ones that are in the textbook.

Thank you so much

https://s.yimg.com/tr/i/861456b443a4470eaf0929e054d56f00_A.png

Answer 1

The issue with probability is always the number of possibilities. For B, the size is 1 part of 4 parts, so that is the probability of 1 spin. But here, we are searching for how many chances of each letter being landed on if we have 2 spins. So the chances of landing on B is 1/4 and the chances of landing on S is also 1/4. If you multiply 1/4 and 1/4, you get 1/16 is the probability of landing on B, R, J, S.

It is unclear if the question is asking for the specific combination being spun on the spinner. That would be

1/4 x 1/4 x 1/4 x 1/4 = 1/256.

https://www.youtube.com/watch?v=EXbIVBr05Yw