You are given the moles of the reactant, sucrose. You will be converting from mols of sucrose to liters of water vapor in the following order: mols reactant → mols product (H2O) → grams H2O → milliliters H2O → liters H2O.
The set up looks like this:
| 5.00 mol sucrose | 11 mol water | 18.02 g water | 1.00 mL water | 1 L water |
| 1 mol sucrose | 1 mol water | 1.00 g water | 1000 mL water |
Explanations for the table: The 11 to 1 ratio is from the coefficients of the sucrose and water in the balanced equation. 18.02 is the molar mass of water. The density of water is 1g/1mL. There are 1000 mL in 1 liter.
Multiplying across cancels out the units until you are left with liters of water. The answer, rounded to 3 significant figures (from the 3 in 5.00 mol originally) should be 0.991 L H2O.
