
Thomas B. answered 12/05/19
PhD in Chemistry with 20+ Years of Teaching Experience
qrxn = – Ccal · (delta)Tcal
qrxn = – 1.229 kJ/°C · 2.19°C
qrxn = – 0.561 kJ
Heats of combustion are almost always expressed in kJ/mol, so…
– 0.561 kJ / 0.0801 mol = –7.01 kJ/mol
Abby B.
Mutinying -1.229 and 2.19 may not result -.561 but -2.69151. Therefore, the correct solution to the question may be -33.601 kj/mol.02/08/22
Enrique G.
wrong10/23/20