How much methanol (CH3OH, in grams) can be formed from 33.7 g of hydrogen? Assume excess CO. CO(g) + 2H2(g) → CH3OH(g)

Answer 1

In this problem you will be using the molar ratios within the equation CO(g) + 2H₂(g) --> CH₃OH(g)

First you need to change the grams of Hydrogen to moles of hydrogen using the molecular weight as your conversion (since there are two hydrogens in the molecule (H₂) you multiply 1.01 g/mole by 2 to get 2.02 g/mole of H₂) then change moles of Hydrogen to moles of methanol using the molar ratio and then convert the moles of methanol to grams of methanol using the molecular weight of methanol as seen below to get your answer. The molar ratio between methanol and hydrogen is 1 to 2. Which means for every 1 mole of methanol there are 2 moles of hydrogen.

33.7gH₂ x 1 mole H₂ x 1 mole CH₃OH x 32.04g CH₃OH = 267.26 gCH₃OH.

2.02g H₂ 2 mole H₂ 1 mole CH₃OH