The change in KE from 15 to 30 mph is 1/2m(30)2 - 1/2m(15)2 = 900/2m - 225/2m = 675/2m
The change in KE from 0 to 15 mph is 1/2m(15)2 - 1/2m(0)2 = 225/2m - 0 = 225/2m
(675/2m)/(225/2m) = 675/225 = 3
Sab G.
asked 11/26/19Starting from rest, you drive down a street, when accelerating from 15 mph to 30 mph, your change in kinetic energy is ________ our change in kinetic energy from
0 mph to 15 mph.
A)One third
B) One half
C) Equal to
D) Two times
E) Three times
I do not understand why the answer is E. Can someone explain? Using the KE=1/2mv^2 equation.
The change in KE from 15 to 30 mph is 1/2m(30)2 - 1/2m(15)2 = 900/2m - 225/2m = 675/2m
The change in KE from 0 to 15 mph is 1/2m(15)2 - 1/2m(0)2 = 225/2m - 0 = 225/2m
(675/2m)/(225/2m) = 675/225 = 3
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Sab G.
Thank you11/26/19