Mike K.

asked • 11/19/19

2NaCl(aq) + 2H20(l) 2Na0H(aq) + Cl2(g) If the sodium hydroxide has a concentration of 0.25 M, how many liters of it are produced from 3.0 moles of chlorine gas?

Stanton D.

Hi Mike K., If that's a reaction, it needs an = sign or an arrow. If it's not, it's a mishmash. But, assuming that .... 2H2O(liq) = 2NaOH(aq) .... is what was intended, you need to: 1) Check that the equation is balanced (it is), or balance it. 2) Using the reaction coefficients, convert the 3.0 mol Cl2 gas into appropriate equivalent NaOH moles, then use the stated concentration to figure the volume for that : Amount = Volume x concentration And there you are. -- Cheers, Mr. d.
Report

11/22/19

1 Expert Answer

By:

Reginald L. answered • 11/24/19

Tutor
New to Wyzant

Ivy League Chemist and Experienced Tutor In Science, French, SAT Prep

See tutors like this
See tutors like this

For equations like this:


2NaCl(aq) + 2H20(l) --> 2Na0H(aq) + Cl2(g)


You can use stoichiometry to find the amount of NaOH produced from a given amount of Cl2 gas. In the equation, 1 mole of Cl2 corresponds to 2 moles of NaOH. As a result, 3.0 moles of Cl2 divided by two yields 1.5 moles of NaOH. The next equation you need is:


Molarity = Moles/Liters. We have the moles of NaOH from above (1.5) and the molarity of the solution was given as 0.25. Rearranged to solve for liters, the equation is


Liters = Moles/Molarity, or the liters = 1.5/0.25 to give your final answer as 6 liters. Hope this helps!

Upvote • 0 Downvote
More
Report

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.