JV K. answered • 01/15/20

Chemistry (General/Organic) Professor with 18 Years of Experience

The chemical reaction equation is already balanced. So, according to this balanced equation, you need 3 moles of Hydrogen gas for every 1 mole of Nitrogen gas. Now we need to find how many moles of Nitrogen is there in 1.4 L of nitrogen. If you remember in the chapter discussing gases and gas laws, there is a conversion factor which is .... At standard conditions (STP), 1 mole of ANY gas would occupy 22.4 L of volume. In other words, if you have 22.4 L of nitrogen, it means you have 1 mole of nitrogen [Remember, mole is just a number of items, but HUGE number => 6.023 x 10^{23} items in 1 mole]

Anyway,

22.4 L = 1 mole

Therefore 1.4 L of N_{2} ==> (1 mol N_{2}/22.4 L N_{2}) * (1.4 L N_{2}) = 0.0625 mol of N_{2}

According to the equation, each mole of N_{2} needs 3 moles of H_{2}

Therefore, 0.0625 mole of N_{2} would need => (3 mol H_{2}/1 mol N_{2})*(0.0625 mol N_{2}) => 0.1875 mol of H_{2}

Now you need to convert the moles of H_{2} to Liters of H_{2} by using the same conversion factor.

==> (22.4 L/1 mol)*(0.1875 mol) ==> 4.2 L of H_{2}