
David G. answered 11/16/19
Patient, Effective math/statistics tutor
Assuming the relation F is
(x1, y1) F (x2, y2) if and only if x1 = x2,
Is this relation reflexive?
Yes, as (x1, y1) F (x1, y1) because x1 = x1.
Is this relation symmetric?
Yes, because if (x1, y1) F (x2, y2), then (x2, y2) F (x1, y1).
This follows from the fact that if x1 = x2, then x2 = x1.
Is this relation antisymmetric?
No, because for F to be antisymmetric we would need
(x1, y1) F (x2, y2) and (x2, y2) F (x1, y1) implies (x1, y1) = (x2, y2). But this is false.
For example (1, 10) F (1, 20) and (1, 20) F (1, 10), but (1, 10) not= (1, 20).
Is this relation transitive?
Yes, because (x1,y1) F (x2, y2) and (x2, y2) F (x3, y3) does imply (x1, y1) F (x3, y3).
This follows because x1 = x2 and x2 = x3 implies x1 = x3.