
Nina Z. answered 11/20/19
M.S. Degree with 20+ years of Teaching Chemistry Experience
Use Born-Haber cycle to figure out enthalpy of formation KBr (s)
K (s) ------> K (g) ΔHsublimation= 110.3 kJ/mol
K (g) ------> K+ + e- IE = 398 kJ/mol
1/2 Br2 (l) ----> Br (g) Eatomization = 210 kJ/mol
Br (g) + e- ------> Br- Ee affinity = -349 kJ/mol
K+ + Br- -------> KBr (s) Elattice = -626 kJ/mol
K (s) + 1/2 Br2 (l) -----> KBr (s) ∆Hf° = 110.3 + 398 + 210 + (-349) + (-626) = -256.7 kJ/mol