Tony M. answered 11/11/19
Multiple years teaching introductory level college chemistry courses
For question 1
The integrated rate law for a 2nd order reaction is 1/[A]t = kt + 1/[A]o
1/[A]t = (.543 l/Ms)(60 s/min)(60 min/hr)(.500 hr) + 1/.0500
1/[A]t = 977.4 + 2 = 979.4
[A]t = 1/979.4 = 1.02 x 10-3 M
At the present time, questions 2 and 3 cannot be answered as there is no data provided.