What is the perimeter, in feet, of a rectangle whose length is twice its width and whose width is 6 feet?

Question

need help on this question. i am trying to answer it but it's not making sense

Answer 1

Width = 6

Length = 2(Width)

Length = 2(6) = 12

Perimeter = sum of all 4 sides of the rectangle = 2(Length) + 2(Width)

= 2(12) + 2(6) = 24 + 12 = 36

36 units is the perimeter of the rectangle.

Answer 2

You are given the width of 6 feet.

You are told that the length is twice the width.....so the length is 12 feet.

The perimeter is the sum of all four sides, and each pair of opposite sides is equal. Add up the 4 sides to get the perimeter