1) KE after falling from a height with intial velocity equal zero = mgh = 1/2mv2 = 2.8*9.81*22 = 6037 J
2) Velocity = sqrt(2gh) = sqrt(2*9.81*22)= 20.78 m/s
3) Car must minimally have KE at top of 16 m hill = the increase of PE at 20 m hill = sqrt(2g(20-16))= 8.86 m/s.
4) Total Energy at point A = 277*50*g +.5*277*3.52 = 137565 J and will be the same at point B (no friction). Therefore the velocity at B = sqrt(2*TE/277)= 31.5 m/s
