How many milliliters of a 8.10 M LiCl solution contain 34.4 g of LiCl?

Question

Express your answer with the appropriate units.

Answer 1

First, we need to find the molar mass of LiCl

M(LiCl) = M(Li)+M(Cl)

M(LiCl) = 6.94 + 35.45

M(LiCl) = 42.39 g / mol

From here, we need to calculate the amount of mols in 34.4g of LiCl by dividing this mass by the molar mass

n = 34.4 / 42.39

n = .8115 mol LiCL

So just to clarify, Molarity = mols/Liters, therefore we can rearrange this equation to Liters = mols/Molarity in order to find the volume we need.

V = .8115 mols / 8.1M

V = .1 L

To convert from L to mL, multiply your Liters by 1000

V (mL) = .1L * 1000mL/L

=100 mL

The answer is 100mL of 8.1M LiCl solution.