Jane A. answered 10/30/19
Experienced Ivy League Math tutor - Patient & Knowledgeable!
Half-life problems have the format of:
A(t) = A(0) (1/2) t/t1/2 where A(0) is the starting amount (or the amount when t = 0)
With the given information that A(0) is 100g (initial amount) and t½ is 10 years:
A(t) = 100 g (1/2) t/10
Thus:
A(0) = 100 g (1/2)0/10 = 100 g
A(20) = 100 g (1/2)20/10 = 25 g
A(60) = 100 g (1/2)60/10 = 1.5625 g
A(t) = 100 g (1/2) t/10
A(10) = 100 g (1/2) 10/10 = 50 g