Let L = length
W = width
Then, L = 2W and Perimeter = 2L + 2W = 2(2W) + 2W = 6W = 9090
So,
W = 9090/6 = 1515
& L = 2W = 3030
Ktya W.
asked 10/29/19A rectangular athletic field is twice as long as it is wide. If the perimeter of the athletic field is
9090
yards, what are its dimensions?
What is the width?
What is the length?
Let L = length
W = width
Then, L = 2W and Perimeter = 2L + 2W = 2(2W) + 2W = 6W = 9090
So,
W = 9090/6 = 1515
& L = 2W = 3030
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