Find an equation of the line that passes through the pair of points (3,-10) and (0,11

Answer 1

First, find the slope of the line.

m=(11- -10)/(0-3)=21/-3=-7.

Next, set up the linear equation in slope intercept form.

y= -7x+b, b is the y intercept when x=0. Use either given point to solve for b but the point (0,11) actually gives you the y intercept, b=11.

Try it in the equation, 11= -7(0) + b, so b=11.

So the linear equation is y = -7x+ 11.