Start with 3p = x
ln 3p = ln x
p ln 3 = ln x
p = log3x = ln x / ln 3
dp/dx = 1/(x ln 3)
and the derivative of 2p is just twice dp/dx
Kyle L.
asked 10/23/19Let f(x) = 2 log3 (x)
f ' (x) =
f ' (2) =
Start with 3p = x
ln 3p = ln x
p ln 3 = ln x
p = log3x = ln x / ln 3
dp/dx = 1/(x ln 3)
and the derivative of 2p is just twice dp/dx
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