Arman G. answered • 10/22/19

Aerospace Engineer

For constant velocity (no acceleration) __d = V*t__

A) d horizontal = d_{h} = V_{h}*t because there's __no horizontal acceleration__ = Vcos(30)*t = 50*cos(30)*3 = __129.9 m__

__Force = m*a and there's gravity which is a force in the vertical direction so there ____IS____ acceleration in the vertical direction so we must use different equation.__

B)

(this comes from integrating acceleration*dt twice from calculus, but if u don't know calculus it's ok, just memorize this formula)

__d = V___{0}** *t + 0.5*a*t^2 ** (note: if a is zero then u just get d = V

_{0}*t) in this case, gravity is accelerating in the

*opposite direction*of motion (its pulling down but ur projectile is being shot up so you have to minus the acceleration). V

_{0 }would be 50*sin(30) to get the vertical velocity and a = -9.8 m/s^2.

d = 50sin(30)*(3 seconds) - 4.9*((3 seconds)^2) = __30.9 m in the vertical direction.__