Gas Law Problem 1.1

Question

Calculate the volume (in liters) occupied by 8.50 g of NH₃ at STP.

Answer 1

Because 1 mole of an ideal gas occupies 22.4 L at STP, we can use this conversion and the molar mass of NH₃(17.03 g) to find the answer.

Volume = 8.50 g NH₃ x 1 mole NH₃/17.03 g NH₃ x 22.4 L/ 1 mole NH₃ = 11.2 Liters

Answer 2

At STP 1 mole of an ideal gas = 22.4 liters

8.50 g NH₃ x 1 mole NH₃/17g x 22.4 liters/mole = 11.2 liters