Starting with 1.8 mol of h2 and excess n2 how much nh3 will be produced?

Answer 1

The balanced chemical equation for the reaction is: 3H₂ + N₂ --> 2NH₃.

We can set up a conversion factor as follows:

1.8mol H₂ * (2 mol NH₃ / 3 mol H₂ ]= 1.2 mol NH₃

So the math would be 1.8 * 2 / 3.