Inactive Tutor answered 12/01/19
Tutor
New to Wyzant
f(x) = Ax(x - 1)2
where A is real and A ≠ 0. Now set
f(2) = 12
and solve for A. You should be able to finish from here.
Juliana S.
asked 10/12/19Polynomial function f(x) of degree 3 with real coefficients that satisfies, Zero of 0 and zero of 1 having multiplicity 2; f(2)=12.
Inactive Tutor answered 12/01/19
f(x) = Ax(x - 1)2
where A is real and A ≠ 0. Now set
f(2) = 12
and solve for A. You should be able to finish from here.
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