We know that Na(Sodium) has molar mass of 22.99 g/mol. Br (Bromine) has molar mass of 79.90 g/mol.
Start with given, which is 2.20 moles of NaBr. We use total molar mass of NaBr to convert from moles of NaBr into grams of NaBr.
22.99+79.90= 102.89 g/mol NaBr.
(2.20 moles NaBr)(102.89 g/mol NaBr) = 226.36 g NaBr
So, there is 226.36 grams of NaBr in 2.20 moles of NaBr.