
Elaine B. answered 10/07/19
Experienced and Patient High School and College Level Chemistry Tutor
You can break up all the aqueous solutions into ions, so:
Zn(NO3)2(aq)→Zn2+(aq)+ 2NO-3(aq)
K2S(aq)→2K+ (aq)+ S2-(aq)
2KNO3(aq)→2K+ (aq)+ 2NO-3(aq)
Keep ZnS together as it is a solid.
The overall ionic equation is: Zn2+(aq)+ 2NO-3(aq) + 2K+(aq) + S2-(aq) →ZnS(s) + 2K+(aq) + 2NO-3(aq)
Eliminate the spectator ions/ions that are on the reactant and product side:
Zn2++ 2NO-3 + 2K+ + S2- →ZnS + 2K+ + 2NO-3
The net ionic equation will be:
Zn2+(aq)+ S2-(aq) →ZnS(s)