Gibbs Free Energy-Carnot cycle

Question

For Adiabatic Process in a Carnot engine(Reversible). We know that ds=o since q= 0 so for Gibbs Free: DeltaG=H-TdS , can we cancel dS since its zero and have it as DeltaG=H??

Answer 1

Yes. This is, like you were saying, the ds will be zero. Also, this makes sense. Because an adiabatic process is being considered, the internal energy of the Carnot's internal system remains the same.