According to the following reaction, how many grams of oxygen gas are required for the complete reaction of 30.2 grams of carbon (graphite)?

Question

According to the following reaction, how many grams of oxygen gas are required for the complete reaction of 30.2 grams of carbon (graphite)?

carbon (graphite) (s) + oxygen (g) carbon dioxide (g)

Answer 1

carbon (graphite) (s) + oxygen (g) carbon dioxide (g)

Ratio = 1:1:1

1. 30.2 g of carbon X (I mole of carbon / 12.011g of carbon) = 2.5144 moles of carbon
2. 2.5144 moles of carbon X (1 mole of oxygen / 1 mole of carbon) = 2.5144 moles of oxygen
3. 2.5144 moles of oxygen X (31.998 g of oxygen gas /1 mole of oxygen gas) = 80.45 g of oxygen gas are required.