Chemistry 103 Chapter 1A

Question

The aluminum in a package containing 76 ft2 of kitchen foil weighs approximately 12 ounces. Aluminum has a density of 2.70 g/cm3. What is the approximate thickness of the aluminum foil in millimeters?

Thickness =  mm

Answer 1

12 oz x 28.35 g/ 1 oz = 340.2 g

(2.70 g/1 cm^3) = (340.2 g/ x cm^3)

x = 126 cm^3 of foil

A = l x w = 76 ft^2

V = l x w x d

V = A x d

d = V/A = 126 cm^3/76 ft^2

(126 cm^3/76 ft^2) x (1 ft/ 12 in) x (1 ft/ 12 in) x (1 in/ 2.54 cm) x (1 in/ 2.54 cm) = the answer in cm (the thickness)

1 cm = 10 mm, so multiply by 10 to get thickness in mm.