
Arturo O. answered 11/26/19
Experienced Physics Teacher for Physics Tutoring
To ensure real coefficients, the complex conjugate of any complex zero must also be a zero..Therefore the 3 zeros are
3
5i
-5i
The form of the polynomial is
f(x) = A(x - 3)(x - 5i)(x + 5i) = A(x - 3)(x2 + 25)
with A real and A ≠ 0. Find A from setting f(2) = -29:
-29 = A(2 - 3)(22 + 25)
You can finish from here.