Marcus H. answered 09/18/19
"No," scolded Yoda. "Do, or do not. There is no try."
First you will need to made a table with three columns...The first column will be a list of unique values from your list
where for the string of number you gave: 1,1,1,2,2,3,3,3,3,3,4,4,6,8,12,13
the unique values are: 1, 2, 3, 4, 6, 8, 12, 13
next to count how many times the unique numbers appear in the string
1 is listed 3 times
2 is listed 2 times
etc.
So now we can make the table
Unique Frequency
1 3
2 2
-----------------------
3 5
4 2
-----------------------
6 1
-----------------------
8 1
-----------------------
12 1
13 1
To determine the range for each interval, you first find the range
Range = 13-1 (highest value - lowest value) = 12
The number of class intervals = range / width
where
number of class intervals = 5
range = 12
width = ?
which can be solved to determine the width
width = range / number of class intervals = 12 / 5 = 2.4 (round up) = 3
We can now determine the width for each class interval
Bin number Class interval Frequency
1 1 - 3 3+2=5
2 4 - 6 5+2=7
3 7 - 9 1
4 10 - 12 1
5 13 - 15 2