gas has a temperature of 234 K. What will was its initial pressure (in atm) if after we increase the temperature to 300 K its pressure reads at 110 kPa?

Question

Can someone please help me answer this question than you very much! it would very helpful if I can get it within today or the evening or at least tomorrow. Thank you very much.

Answer 1

Use the combined gas law:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂ but since volume does not change and remains constant, this can be simplified to

P₁ / T₁ = P₂ / T₂

Therefore P₁ / 234 = 110 / 300

Therefore P₁ = (110 * 234)/300 = 85.8 kPa

Since there are 101.325 kPa in 1 atm, then the initial pressure is

85.8/101.325 = 0.847 atm