Density of piece of metal

Question

A piece of metal weighing 45.450 g was submerged in a graduated cylinder containing 15.0 ML of water after it was submerged the volume rose to the level of 33.5 ML what is the density of the piece of metal

Answer 1

D = M /V M= 45.450 g V= 33.5 - 15.0 = 18.5 mL

D = 45.450 g / 18.5 mL = 2.46 g / mL

Answer 2

Density is related to mass and volume by the relationship:

D = mass/volume

therefore since mass is 45.450g and volume is (33.5 - 15.0) mL (the change in volume), density is given by:

D = 45.450/18.5 g/mL = 2.457 g/mL