If John cleaned 1/3 portion of the house and Ben cleaned 2/7 portion of the house and the left portion was cleaned by Jack ,how much did jack cleaned and who cleaned the largest part of the house

Answer 1

Let's choose 21 as a common denominator, then

k

1/3 = 7/21

2/7 = 6/21

So, since the total must add to 1, the remainder = 8/21 (7+6+8 = 21)

Now, which is the largest

1/3 = .333

2/7 = .286

8/21 = .381 but you knew this was the largest since 8>7>6 !