Calculate the amount of CO2 (in grams) that could be produced from 76 g of C3H8?

Answer 1

Calculate the amount of CO2 (in grams) that could be produced from 76 g of C3H8?

First write out the chemical reaction: C3H8 + 5O2 --> 3CO2 + 4H2O (This is a combustion reaction, it always looks like: some carbon compound such as C3H8 plus O2, and that reacts to give you CO2 and H2O. The moles are just different in each reaction!)

Next, find the molar mass of C3H8: 44.1 g/mol

Next, convert 76 g of C3H8 to moles, convert moles of C3H8 to moles of CO2, then convert from moles of CO2 to g of CO2.

Here's how that will look: 76 g C3H8 * 1 mol C3H8 / 44.1 g/mol C3H8 = 1.723 mol C3H8

1.723 mol C3H8 * 3 mol CO2 / 1 mol C3H8 = 5.17 mol CO2

Now take the 5.17 mol of CO2 and convert it to grams. To do this, we need CO2's molar mass, which is: 44.01 g/mol. This will look like this:

5.17 mol CO2 * 44.01 CO2 g/mol / 1 mol CO2 = 227.53 g of CO2 that can be produced from 76 g of C3H8

The answer is 227.53 g of CO2!

*The molar mass of C3H8 is close to the molar mass of CO2, the same molar mass was not used for both.

Answer 2

I would refer you to the answer already given at

https://www.wyzant.com/resources/answers/713513/calculate-the-amount-of-co2-in-grams-that-could-be-produced-from-76-g-of-c3