Hitting a golf ball on the moon vs earth

Question

A golf ball is hit on the moon which has a free-fall acceleration 1/6 of its value on earth. The ball is hit at a speed of 28m/s at an angle of 35 degrees. How far did the golf ball travel? Ignoring air resistance, how far would it travel on earth?

I did 1/6*9.8=1.63 for g on the moon

Then used R=(Vi^2sin2theta)/g

so on the moon R=((28^2)sin2*35)/1.63=452m

and on earth R=((28^2)sin2*35)/9.8=75.2m

I am just not sure if I did this properly. My professor hasn't really gone over when to use the range equation but I would assume range would equal the distance traveled therefore can be used for this problem. If not the how would I go about solving this?

Answer 1

You used the correct formula and arrived at the right answer.