A technical machinist is asked to build a cubical steel tank that will hold 60L of water.Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest

Answer 1

Dimensional Analysis problem.

You must use an equivalent, 1 L = 1 dm³ or 1 mL = 1 cm³ to convert the volume from L to a cubic dimension.

60 L x ^{1 dm3} /_{1 L} = 60 dm³

Volume of a cube = length³ ; or length = cube root of Volume

length = cube root of 60 dm³ = 3.9 dm

Convert dm to m for answer: 3.9 dm x ^{1 m} /_{10 dm} = 0.39 m