Cherylyn L. answered 09/06/19
PhD in Chemistry with 10 years of Tutoring and Teaching Experience
Given: In 1 yr the mass of nitrogen in liquid (river) is m = 1.80 x 105 mg,
and the volume of liquid is V = 6.00 x 105 L
Concentration = mass (mg)/volume (L) = 1.80 x 105 mg / 6.00 x 10^5 = 0.300 mg/L