Stephany B.
asked • 09/02/19A jogger takes the following route to the entrance of their local park: north 120m, west 100m, south 35m, and finally west 50m. It takes them 2 minutes 18 seconds to reach the park entrance.
a) What distance did the jogger travel?
b) What is the displacement of the jogger as she enters the park?
c) What is the average speed of the jogger?
d) What is the average velocity of the jogger?
Rick R. answered • 09/02/19
(a) d = 120m + 100m + 35m + 50m = 305m
(b) Δx = –100m – 50m = –150m
Δy = 120m – 35m = 85m
|Δr|2 = Δx2 + Δy2 = (-150)2 + (85)2 = 22500 + 7225 = 29725m2
|Δr| = √29725 = 172.4m
∠Δr = arctan(Δy/Δx) = 29.5º North of West = 150.5º counterclockwise with respect to due East
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
