
Ralph K. answered 01/17/15
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Effective Mathematics, Physics and Chemistry Tutor
Hi Seleah,
Since we can't use Algebra let's try a successive approximation numerical technique. We will guess a starting point let's arbitrarily use 15 years old for Harriet's age. We can't use anything less than 11 years because the problem inclues her age from 10 years earlier, and in 10 years she will be 25 years old. That is 5 times as old as she was 10 years earlier.
(15+10)/(15-10) = 25/5 = 5
Since we are trying to find a number where she is 3 times as old, the age needs to increase. Let us try 3 years older so 18 years old.
(18+10)/(18-10) = 28/8 = 3.5
We are still a bit too high so let us try 4 years more, 22 years old.
(22+10)/(22-10) = 32/12 = 2 2/3
We have overshot 3 so let's go back halfway or -2 to 20 years old.
(20+10)/(20-10) = 30/10 = 3
Therefore 20 years old is Harriet's age
I hope this helps