chemistry molarity

Question

What volume of a 0.33 M sucrose (C12H22O11) solution can be diluted to prepare 25 mL of a 0.025 M solution?

Answer 1

Hi Rosyy! This is a great example of the dilution equation: M₁V₁ = M₂V₂

M₁ is the initial concentration (Molarity) of our solution

V₁ is the initial volume of our solution

M₂ is the final concentration (Molarity) of our solution

V₂ is the final volume of our solution

Now that we have our equation, we need to assign the values that are given in the question to the variables in our equation.

M₁ = 0.33 M (initial concentration of sucrose)

V₁ = x (this is what we are looking for)

M₂ = 0.025 M (final concentration of sucrose)

V₂ = 25 mL = 0.025 L (converting from mL to L by dividing 25 mL by 1000 since there are 1000 mL in 1 L)

The next step is to plug in our values and solve for the unknown.

M₁V₁ = M₂V₂

(0.33 M) (x) = (0.025 M) (0.025 L)

(x) = ((0.025 M)(0.025 L)) / (0.33 M) Dividing both sides by 0.33 M to get x by itself. Units 'M' cancel.

x = 0.00189 L, which can be converted back to mL by multiplying by 1000

x = 1.89 mL

So we would need to add 1.89 mL of our original 0.33 M sucrose solution to a new container to make a 25 mL solution of 0.025 M sucrose.

If you need any more help or clarification, please don't hesitate to reach out!