How many microliters of a 832.0 ppm Co 2+ 832.0 ppm Co2+ stock solution are required to prepare 11.00 mL 11.00 mL of a 19.0 ng/𝜇L Co 2+ 19.0 ng/μL Co2+ solution?

Question

I have no idea how to solve this so a little help would be appreciated.

Answer 1

The question is a bit vague. Is there only one Co²⁺/Co³⁺ solution that is to be diluted? If so:

1 ng/μL = 1 ppm. so 832.0 ppm = 832.0 ng/μL.

using a simple dilution formula, C₁ • V₁ = C₂ • V₂ (832.0 ng/μL) V = (19.0 ng/μL)(11000 μL)

V = 251 μL