Mark M. answered 08/22/19
Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = 5x - 1
f(∑) - f(Ω) = 5(∑) - 1 - [ 5(Ω) - 1] = 5(∑) - 5(Ω) = 5(∑ - Ω)
Vanessa M.
asked 08/22/19How would I go about solving this problem?
Mark M. answered 08/22/19
Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = 5x - 1
f(∑) - f(Ω) = 5(∑) - 1 - [ 5(Ω) - 1] = 5(∑) - 5(Ω) = 5(∑ - Ω)
Mariana P. answered 08/22/19
Experienced, Patient in all Math levels and Big Data technologies
is the delta and omega defined or just variables ?
if there are variables you just substitute the values of x within corresponding ones in each function
since f(x) is in term of x then f(delta) = 5*delta -1 and f(omega) = 5*omega -1
then you have to perform the operation f(delta) -f(omega) = 5delta -1 -f(omega)-1 = f(delta)-f(omega)-2
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