A box contains some bottons.1/4 contain black, 1/8 are red, and the rest are white.there are 948 more white than red bottons. ,how many bottons in total?

Answer 1

Four equations are needed because there are four variables:

Total buttons (T)

Black buttons (B)

Red buttons (R)

White buttons (W)

T = B + R + W

B = (1/4)T

R = (1/8)T

W = 948 + R

Substitute R into the equation for W:

W = 948 + [(1/8)T]

Substitute B, R, and W into the equation for T:

T = [(1/4)T] + [(1/8)T] + [948 + (1/8)T]

Group common terms:

T = (1/4)T + (1/8)T + (1/8)T + 948

Convert to common denominators:

T = (2/8)T + (1/8)T + (1/8)T + 948

Add common terms:

T = (4/8)T + 948

Simplify:

T = (1/2)T + 948

Subtract (1/2)T from both sides:

T - (1/2)T = (1/2)T - (1/2)T + 948

(1/2)T = 948

Multiply both sides by 2 to cancel the 1/2:

(1/2)T * 2 = 948 * 2

T = 1,896

If you have any questions that will help you better understand this solution, please feel free to ask!

Answer 2

Eazie cheezie:

black=box/4

red=box/8

white=(1-1/4-1/8)box=(8/8-2/8-1/8)box=5/8box

Now,

white=red+948

5/8box=1/8box=948

4/8box=948

1/2box=948

box=948x2

box=1896