Give the following reaction N2 (g) + 3H2 (g) = 2NH3 (g) , how many liters of H2 are required to produce 47 moles of NH3

Answer 1

Answer 2

Let's set this up as a dimensional analysis problem. Also, given that all of compounds in this reaction are gas, we will use the fact that one mole of a gas takes up 22.4 Liters.

47 moles NH₃ (3 moles H₂/ 2 moles NH₃ ) (22.4 Liters / 1 mole) = 1579.2 Liters

Answer 3

Assuming that the reaction is occurring at STP, once we get the moles of H₂, it will require just conversion of 22.4 L/mol.

47 mol NH₃ * 3 H₂/ 2 NH₃= 70.5 mol H₂

70.5 mol H₂ * 22.4 L/mol= 1579.2 L H₂

Answer 4

Please see video answer!