In snell´s law, find θ2 in n1sinθ1=n2sinθ2

Question

Step by step please. I dont seem to understand it

Answer 1

Write n₁sin θ₁ = n₂sin θ_2.

Then n₁sin θ₁ ÷ n₂ = n₂sin θ₂ ÷ n₂.

(n₁/n₂₎sin θ₁ = sin θ₂.

Finally, θ₂ = arcsin [(n₁/n₂)sin θ₁].

Answer 2

The steps are pretty simple, Jessica. theta1 is the angle of incidence of alight wave as it approaches a barrier between two mediums with different indexes of refraction(n1 and n2). Theta 2 is the angle of reflection.

So, a light wave approaches travelling along theta one througn1, crosses the line and is reflected into n2 at a different angle.

So, n1(sin theta 1) = n2(sin theta 2) - divide both sides by n2

Sin (theta2) = n1 (sin(theta1) / n2

So, theta2 = sin^-1 (sin theta1)* n2/n1