TIM B. answered • 8d

50 YEAR PHYSICS OBSESSION; READY TO TUTOR

Write n_{1}sin θ_{1 }= n_{2}sin θ_{2.}

Then n_{1}sin θ_{1 }÷ n_{2 }= n_{2}sin θ_{2 }÷ n_{2}.

(n_{1}/n_{2)}sin θ_{1} = sin θ_{2}.

Finally, θ_{2 }= arcsin [(n_{1}/n_{2})sin θ_{1}].