1) You are given molarity and grams of calcium phosphate, Ca3(PO4)2. You can get moles of Ca3(PO4)2 from grams using molar mass of calcium phosphate which is 310.174g
74.69 g×(1mole/310.174g) = 0.2408 moles of Calcium phosphate
To determine the volume of calcium phosphate, use the relation:
Molarity = moles/ volume in liters or
Volume of Ca3(PO4)2 sol = moles of Ca3(PO4)2/molarity of Ca3(PO4)2
= 0.2408/0.246 = 0.979 liter of calcium phosphate
2) To determine how many ml of propyl alcohol in 6.0% solution, think of 6% sol means 6 ml iso prop alcohol in 100 ml sol so to determine vol of iso prop alcohol in 735.0 ml multiply
.06×735.0 = 44 ml of iso propyl alcohol
3) Strong electrolytes ionize completely (100%) into their ions(cations and anions) when dissolved in water and readily conduct electricity through them
Weak electrolytes dissociate only partially(1 to10%) in aq. Solution. They are poor conductors of electricity.
Non electrolytes do not exist in ionic forms in aqueous solution and do not dissociate into ions when melted. They are non conductors of electricity
