How do I solve this problem

Question

A gas sample has a volume of 0.306 L with an unknown temperature. The same gas has a volume of 0.200 L when the temperature is 30. ∘C, with no change in the pressure or amount of gas.

Answer 1

I am guessing you want to determine the unknown temperature. Since the volume changes when you change the temperature and pressure P and amt of gas n remains constant, use Charle’s law

V1/T1 = V2/T2. Change temp in Kelvin scale

.306L/T1 = .200L/ 303K. (30 + 273) = 303 K

T1. = 464K

= 464 —273= 191degree C