
Jim L. answered 07/26/19
Personable, effective English, Math and Science Tutor
In the first reaction, the mole ratio is 2 mol NaN3 to 2 Mol Na and 3 Mol N2
So the first reaction has 130g of NaN3, or 2 moles of NaN3, which creates 3 moles of N2 and two moles of sodium
In the second reaction, 10 moles of sodium create one mole of N2, so the two moles of Na from the first reaction create 0.2 moles of N2.
So, the total moles of N2 produced are 3 + 0.2 = 3.2 moles
V = ?
P = 1 atm
T = 313 deg K
n = 3.2 moles
R = 0.0821
Solve for V V = 82.2 L