(8,-7) (6,3) what is its standar and general form?

Question

The center of the diameter of the circle are (8,-7) and (6,3)

Answer 1

THe radius is sqrt ( (8-6)^2 + (-7 -3)^2 )

= sqrt( 2^2 + (-10)^2 )

= sqrt( 4 + 100)

= sqrt(104)

If (8.-7) is the center then the equation is (x-8)^2 + (y+7)^2 = 104

if (6,3) is the center then the equation is (x-6)^2 + (y-3)^2 = 104